Economy of evaporator

Q. An evaporator is to be fed with 5000 kg/hr solution containing 10% solute by weight. The feed at 313 K is to be concentrated to a solution containing 50% solute by weight. Steam is available at an absolute pressure of 303 kPa. Saturation temperature of steam is 410 K. The overall heat transfer coefficient is 1750 W/m²·K. Calculate: (a) Heat transfer area that should be provided. (b) Economy of an evaporator. Given: (C_p) of feed = 4.187 kJ/kg·K At 313 K, enthalpy of feed = 170 kJ/kg At 373 K, enthalpy of vapour = 2676 kJ/kg At 373 K, enthalpy of liquid = 419 kJ/kg At 410 K, enthalpy of vapour = 2745 kJ/kg At 410 K, enthalpy of liquid = 563 kJ/kg

Subject: Chemical engineering · Topic: Heat transfer